乙0.6m/s
设甲、乙的速度为v甲、v乙,
∵v=s/t
,
∴在t=1min=60s内甲走的距离：
s甲=v甲t=1m/s×60s=60m,
乙走的距离：
s乙=v乙t=v乙×60s,
∵两人从同一地点同时相背而行,
∴s=s甲+s乙=96m,
即：60m+v乙×60s=96m,
解得：v乙=0.6m/s．
答：乙的速度为0.6m/s．