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2(sin^6 α +cos^6α)-3(sin^4a+cos^4α)
mingbaidian
人气:252 ℃ 时间:2020-06-13 02:38:23
解答
2(sin^6 α +cos^6α)-3(sin^4α+cos^4α)
=2(sin^2α+cos^2α)(sin^4α-sin^2αcos^2α+cos^4α)-3sin^4α-3cos^4α
=-sin^4α-2sin^2αcos^2α-cos^4α
=-(sin^α+cos^2α)^2=-1
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