[(1+2^-(1/32)]*[(1+2^-(1/16)]*[(1+2^-(1/8)]*[(1+2^-(1/4)]*[(1+2^-_数学解答

[(1+2^-(1/32)]*[(1+2^-(1/16)]*[(1+2^-(1/8)]*[(1+2^-(1/4)]*[(1+2^-(1/2)]

人气：472 ℃　时间：2020-04-13 21:53:24

解答

[(1+2^-(1/32)]*[(1+2^-(1/16)]*[(1+2^-(1/8)]*[(1+2^-(1/4)]*[(1+2^-(1/2)]
=[(1-2^-(1/32)]*[(1+2^-(1/32)]*[(1+2^-(1/16)]*[(1+2^-(1/8)]*[(1+2^-(1/4)]*[(1+2^-(1/2)]/[(1-2^-(1/32)]
=[1-2^(-1)]/[(1-2^-(1/32)]
=1/[(2-2^(31/32)]为什么这样做，有什么方法？