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xx+2xy+yy-4x-4y-12的因式分解是多少
人气:213 ℃ 时间:2019-08-22 11:39:14
解答
x²+2xy+y²-4x-4y-12
=(x²+2xy+y²)-(4x+4y)-12
=(x+y)²-4(x+y)-12
=[(x+y)+2][(x+y)-6]
=(x+y+2)(x+y-6)
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