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已知X+4Y-3Z=0,4X-5Y+2Z=0(XYZ≠0),求(3x²+2xy+z²)/(x²+y²)的值,
人气:449 ℃ 时间:2019-08-16 22:05:18
解答
X+4Y-3Z=0 (1)
4X-5Y+2Z=0 (2)
(1)*4-(2),得:3Y=2Z
(1)*2-(2)*3,得:2X=Y
把Z=3/2 Y,X=1/2 Y 带入式(3x²+2xy+z²)/(x²+y²),解得为16/9
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