a²x²-2ax+1=a²-x如何解?要详细过程!
a²x²-2ax+x+1-a²=0
a²x²-(2a-1)x+1-a²=0
x=(2a-1±√[(2a-1)²-4a²(1-a²)])/2a²
x==[2a-1±√(4a^4-4a+1)]/2a²