我原来做过,现抄来：用罗比达法则：lim(x→0)((1+x)^(1/x)-e)/x=lim(x→0)((1+x)^(1/x))'现设y=(1+x)^(1/x),lny=ln(x+1)/x,求导得：y'/y=(x/(x+1)-ln(x+1))/x^2=(x-(x+1)ln(x+1))/(x^2(1+x))limy'=limylim(x-(x+1)ln...