M={x|y=lg(1-x)/x}
={x|(1-x)/x＞0}
={x|x(x-1)＜0}
={x|0＜x＜1}
N={y|y=x^2+2x+3}
={y|y=(x+1)^2+2}
={y|y≥2}
所以CrM={x|x≤0或x≥1}
所以(CrM )∩N={x|x≥2}