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已知(x+1)2+|y-1|=0,求2(xy-5xy2)-(3xy2-xy)的值.
人气:390 ℃ 时间:2019-08-17 18:00:08
解答
2(xy-5xy2)-(3xy2-xy)=(2xy-10xy2)-(3xy2-xy)=2xy-10xy2-3xy2+xy=(2xy+xy)+(-3xy2-10xy2)=3xy-13xy2,∵(x+1)2+|y-1|=0∴(x+1)=0,y-1=0∴x=-1,y=1.∴当x=-1,y=1时,3xy-13xy2=3×(-1)×1-13×...
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