已知：x+3／x+2=1／根号3+根号2+1,求x-3／2x-4÷(5／x-2－x-2)的值(x+3)/(x+2) = 1/(√3_其他解答

已知：x+3／x+2=1／根号3+根号2+1,求x-3／2x-4÷(5／x-2－x-2)的值
(x+3)/(x+2) = 1/(√3+√2+1)

人气：361 ℃　时间：2019-09-25 08:37:18

解答

取倒数(x+2)/(x+3)=√3+√2+1(x+2)/(x+3)-1=√3+√2-1/(x+3)=√3+√2原式=[(x-3)/(2x-4)]÷[5-(x+2)(x-2)]/(x-2)]=[(x-3)/2(x-2)]×[-(x-2)/(x²-9)]=[(x-3)/2(x-2)]×[-(x-2)/(x+3)(x-3)]=-1/(x+3)=√3+√2...