方程4x^2-7x-3=0的两根为x1,x2,所以x1+x2=7/4,x1x2=-3/4,x2/(x1+1)+x1/(x2+1)=（x1^2+x2^2+x1+x2）/(x1x2+x1+x2+1)x1^2+x2^2=（x1+x2）^2-2x1x2=73/16,所以x2/(x1+1)+x1/(x2+1)=（73/16+7/4）/（-3/4+7/4+1）=101/32...