求二元函数方程组sin(x-y)=0;cos(x+y)=0的解
人气:324 ℃ 时间:2020-10-02 01:29:00
解答
sin(x-y)=0sinxcosy- cosxsiny =0cos(x+y)=0cosxcosy-sinxsiny = 0sinxcosy- cosxsiny = cosxcosy-sinxsinysinx-cosxtany= cosx- sinxtanysinx-cosx= -tany(sinx-cosx)(sinx-cosx)(1-tany)=0sinx = cos xx = 2k...
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