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求cosπ/9*cos2π/9*cos4π/9的值
如题
人气:371 ℃ 时间:2020-04-04 03:17:15
解答
利用2倍角公式cosπ/9*cos2π/9*cos4π/9=[sinπ/9*cosπ/9*cos2π/9*cos4π/9]/sinπ/9=[1/2sin2π/9*cos2π/9*cos4π/9]/sinπ/9=[1/4sin4π/9*cos4π/9]/sinπ/9=[1/8sin8π/9]/sinπ/9=[1/8sinπ/9]/[sinπ/9]=1...
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