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若tanα=3,则(sin^3α+2cos^3α)/(sin^3α-2cos^3α)
人气:419 ℃ 时间:2020-06-17 05:39:38
解答
(sin^3α+2cos^3α)/(sin^3α-2cos^3α)
=(sin^3α/cos^3α+2)/(sin^3α/cos^3α-2)
=(tan^3α+2)/(tan^3α-2)
=(3^3+2)/(3^3-2)
=29/25
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