X/2=Y/3=Z/4 2X-Y+3Z=26 2元1次方程
人气：126 ℃ 时间：2020-02-03 04:40:53
解答
X/2=Y/3=Z/4=K
X=2K,Y=3K,Z=4K
∵2X-Y+3Z=26
把上面三个式子带入,得：
4K-3K+12K=26
13K=26
K=2
∴X=4,Y=6,Z=8
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