不等式组｛k-1＜x＜k+2,3＜x＜5的解集实际上是k-1＜x＜k+2,3＜x＜5的交集,即共有的范围
又不等式组｛k-1＜x＜k+2,3＜x＜5的解集是3＜x＜k+2
所以可知
k-1＜3,k+2＜5,即k＜3