（cosα+3sinα）/(6sinα-2cosα)=2cosα+3sinα=(6sinα-2cosα)*25cosα=9sinα tanα=5/9 sin2^α+cos2^α=1所以cosα=9/(106)^0.5 sinα=5/(106)^0.5sin2^α+3sinαcosα-2cos2^α=-1/53