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5xy^2-{2x^y-[3xy^2-(xy^2-2x^2y)]/(-1/2xy)}
人气:111 ℃ 时间:2020-02-03 16:57:54
解答
原式=5xy^2-[2x^2y-(3xy^2-xy^2+2x^2y)/(-1/2xy)]
=5xy^2-[2x^2y-(2xy^2+2x^2y)/(-1/2xy)]
=5xy^2-(2x^2y+4y+4x)
=5xy^2-2x^2y-4y-4x
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