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数学
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计算:(lg2)的平方+lg5乘以lg20减去1
人气:367 ℃ 时间:2019-11-11 00:59:15
解答
lg2)^2+lg5*lg20-1
=(lg2)^2+lg5lg(4*5)-1
=(lg2)^2+lg5(lg2^2+lg5)-1
=(lg2)^2+lg5*lg2^2+(lg5)^2-1
=(lg2)^2+2lg5*lg2+(lg5)^2-1
=(lg5+lg2)^2-1
=(lg10)^2-1
=1-1
=0
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