设所求椭圆的标准方程为：x^2/a^2+y^2/b^2=1因,焦距=4,即,2c=4,c=2又,c^2=a^2-b^2=2^2故,a^2-b^2=4 ------(1)因,椭圆过P[(2/3)*根号,(-2/3)*根号6]将P点坐标代入椭圆标准方程中,得：{[(2/3)*根号6]^2/a^2}+{[(-2/3)*...