设等比数列(an},若S3+S6=2S9,求证:a2,a8,a5成等差数列
人气:420 ℃ 时间:2020-05-19 00:47:24
解答
证:S3+S6=2S9a1(q^3-1)/(q-1)+a1(q^6-1)/(q-1)=2a1(q^9-1)/(q-1)q^3-1+q^6-1=2q^9-2q^3+q^6=2q^92q^6-q^3-1=0(q^3-1)(2q^3+1)=0q^3=1或q^3=-1/2q^3=1时a2+a5=a1q+a1q^4=a1q(1+q^3)=2a1q2a8=2a1q^7=2a1q2a8=a2+a5a2,...
推荐
- 设Sn是等比数列的前n项和,S3,S9,S6成等差数列 求证a2,a8,a5成等差数列
- 已知数列an是等比数列,前n项和为Sn,若S3,S9,S6成等差数列,求a2,a8,a5成等差数列
- 已知等比数列{an}各项为实数且公比为q,前前n项和为Sn,S3,S9,S6成等差数列,求证:a2,a8,a5成等差数列
- 已知Sn是等比数列{an}的前n项和,已知S3,39,S6成等差数列,求证a2,a8,a5成等差数列.
- 已知Sn是等比数列{An}的前n项和,S3,S9,S3成等差数列,求证a2,a8,a5成等差数列
- -Hello,may I speak to Mrs Zhang,please?-Sorry,she is not in .She ___the school gym.
- 我最感动的时刻 - 作文 500字
- 一个数的2又5分之1倍是1又5分之4,这个数是多少?
猜你喜欢