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3倍根号下a3-1-3a2+3a 化简为?
人气:130 ℃ 时间:2020-08-30 17:44:18
解答
3倍根号下a3-1-3a2+3a
=3倍根号下(a-1)(a2+a+1)-3a(a-1)
=3倍根号下(a-1)(a2-2a+1)
=3倍根号下(a-1)^3
=a-1
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