已知y-2x=0.求代数式(x^2-y^2)(x^2-xy+y^2)/(x^2+xy+y^2)(x^2-y^2)._数学解答

已知y-2x=0.求代数式(x^2-y^2)(x^2-xy+y^2)/(x^2+xy+y^2)(x^2-y^2).

人气：240 ℃　时间：2020-06-19 15:14:59

解答

y-2x=0
y=2x
(x^2-y^2)(x^2-xy+y^2)/(x^2+xy+y^2)(x^2-y^2).
=(x^2-xy+y^2)/(x^2+xy+y^2)
=(x^2-2x^2+4x^2)/(x^2+2x^2+4x^2)
=3x^2/7x^2
=3/7