> 数学 >
反三角函数2个问题,急求
1:tan(arctan1/5+arctan3)
2:cos【2arctan(3/4)】
都是求值
人气:478 ℃ 时间:2020-06-12 14:47:48
解答
tan(arctan1/5 + arctan3)
=(tan(arctan1) + tan(arctan3)) /( 1-tan(arctan1/5) tan(arctan3))
=(1/5+3) / (1-1/5*3)
=8
2注意:勾3股4弦5
arctan(3/4)=arccos(4/根号(3*3+4*4))=arccos(4/5)……(1)
arctan(3/4)=arcsin(3/5)……………………………………(2)
cos[2archtan(3/4)]=cos[archtan(3/4)]*cos[archtan(3/4)]-sin[archtan(3/4)]*sin[archtan(3/4)]………………(3)
将(1)和(2)代入(3)即得到结果.
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