>
数学
>
1+2分之1²-2²+2+3分之2²-3²+.+99+100分之99²-100²
人气:278 ℃ 时间:2020-03-25 06:35:48
解答
您好:
1+2分之1²-2²+2+3分之2²-3²+.+99+100分之99²-100²
=(1+2)(1-2)/(1+2)+(2+3)/(2-3)+...+(99+100)(99-100)/(99+100)
=-1-1-...-1
=-99
不明白,可以追问
如有帮助,记得采纳,谢谢
祝学习进步!
推荐
(1+2分之1²-2²)(2+3分之2²-3²).(99+100分之99²-100²)
计算:1²-2²+3²-4²+.+99²-100²=?
帮忙解答100²- 99²﹢ 98 ²+···+ 2 ²-1²
1²+2²+3²+4²……+99²+100²
(99²+198+1)²分之100²
急求春游作文开头
Other'S help god helps those who help 什么意思
天上最亮的星星..
猜你喜欢
童年 第四章主要内容
设Sn为数列{an}的前n项和,Sn=kn2+n,n∈N*,其中k是常数. (Ⅰ)求a1及an; (Ⅱ)若对于任意的m∈N*,am,a2m,a4m成等比数列,求k的值.
she happend to be there at this time yesterday m
一小学英语改错题
3.2克二氧化硫与几克三氧化硫所含的氧原子个数相同
It is only during the time when the mount lock is obtained that will affect other jobs.
Our teacher is going to have me_the desk with you.
same,the,every,country,traffic,light,are,the,in.连词成句
© 2024 79432.Com All Rights Reserved.
电脑版
|
手机版