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设tan(α+8/7π)=a 求证sin(22π/7+α)+3cos(α-20π/7)/ sin(20π/7-α)-cos(α+22π/7)=a+3/-a
人气:373 ℃ 时间:2020-05-21 10:17:21
解答
tan(α+8π/7)=tan(π+α+π/7)=tan(α+π/7),即:tan(α+π/7)=asin(22π/7+α)+3cos(α-20π/7)/ sin(20π/7-α)-cos(α+22π/7)=(sin(3π+π/7+α)+3cos(3π-2π/7-α))/(sin(3π-2π/7-α)-cos(3π+π/7...
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