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因式分解:2ax-10ay+5by-bx 计算:已知a-b=5,b-c=3,求a^2+b^2+c^2-ab-ac-bc的值
不会啊,这是两道题
人气:301 ℃ 时间:2020-05-01 04:40:07
解答
2ax-10ay+5by-bx =2a(x-5y)-b(x-5y)=(2a-b)(x-5y)由a-b=5,b-c=3得a-c=8又(a-b)^2=a^2=b^2-2ab (a-c)^2=a^2=c^2-2ac (c-b)^2=c^2=b^2-2bc 等式两边分别相加,得(a-b)^2+(a-c)^2+(c-b)^2=2a^2+2b^2+2c^2-2ab-2ac-2bc...
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