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已知a是第三象限角且f(a)=sin(兀-a)cos(2兀-a)tan(-a-3兀/2)/cot(-a-兀)sin(-a-兀)
(1)化简f(a)
(2)若cos(a-3兀/2)=1/5,求f(a)的值
(3)若a=-1860度,求f(a)的值
人气:171 ℃ 时间:2020-02-05 16:42:24
解答
(1)化简f(a)
f(a)=sin(兀-a)cos(2兀-a)tan(-a-3兀/2)/cot(-a-兀)sin(-a-兀)
=sina*cosa*cota/(-cota)*sina
=-cosa.
(2)若cos(a-3兀/2)=1/5,求f(a)的值
cos(a-3兀/2)=-sina=1/5,
f(a)=-cosa=±4√6/5.
(3)若a=-1860度,求f(a)的值
f(a)=-cos(-1860°)=-cos(-360°*5-60°)
=-cos(-60°)=-cos60°=-1/2.
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