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(sin(a-pai)cot(a-2pai))/(cos(a-pai)tan(a-2pai))
人气:439 ℃ 时间:2020-04-14 22:48:51
解答
(sin(a-pai)cot(a-2pai))/(cos(a-pai)tan(a-2pai))
=(-sin(pai-a)cot(a))/(cos(pai-a)tan(a))
=(-sin(a)cot(a))/(-cos(a)tan(a))
=-cosa/(-cos(a)tan(a))
=cota.
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