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matlab 如何做分段函数的绘图 y=sin(x)*(-2*pi=0)
人气:480 ℃ 时间:2019-12-07 23:18:35
解答
clc
x1=-2*pi:0.01:0;
y1=sin(x1);
x2=0:0.01:2*pi;
y2=exp(x2);
plot(x1,y1,'r',x2,y2,'b')
axis([-2*pi 2*pi -2 20])
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