铁铜
将10铁棒插入100硫酸铜溶液中,过一段时间,取出铁棒洗涤干燥称其质量为11.2,问干燥后的铁棒上,铜的质量分数?
人气：429 ℃ 时间：2020-04-22 20:24:47
解答
设铁棒反应了x g,那么剩下的是（10-x）g
Fe+CuSO4=FeSO4+Cu
56 64
x y
生成的Cu为=64x/56,那么最后干燥后的铁棒质量=剩余的铁+生成的铜
10-x+64x/56=11.2
x=8.4g.所以生成Cu质量为9.6g
则,铜的质量分数为9.6/11.2=85.7%
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