> 数学 >
(3-x分之x-1)平方÷(x平方-6x+9分之9-x平方)平方*x平方-2x+1分之6+2x
(a+b)平方分之1 -a+b分之2 通分 急
人气:288 ℃ 时间:2020-03-18 02:23:11
解答
(3-x分之x-1)平方÷(x平方-6x+9分之9-x平方)平方*x平方-2x+1分之6+2x
=[(x-1)/(3-x)]²÷[(9-x²)/(x²-6x+9)]²*[(6+2x)/(x²-2x+1)]
=[(x-1)/(3-x)]²÷[(x²-6x+9)/(9-x²)/]²*[(6+2x)/(x²-2x+1)]
=[(x-1)/(3-x)]²*[(x-3)²/(x+3)(3-x)]²*[2(3+x)/(x-1)²]
=[(x-1)²/(3-x)²]*[(x-3)^4/(x+3)²(3-x)²]*[2(3+x)/(x-1)²]
={1/(x+3)]*[2]
=2/(x+3)
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版