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求下列三角函数的值:(1)sin(-67π/4)(3)cos398°13'
人气:431 ℃ 时间:2020-10-01 22:39:38
解答
(1)sin(-67π/4)=sin(-67π/4+16π)=sin(-3π/4)=-sin(3π/4)=-√2/2
(3)cos398°13' =cos(398°13'-360° )=cos(38°13‘)=cos(38°+13/60)=cos38.217°=0.7857
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