(x+3)/(x+2)+(2-x)/(x²-4)
=(x+3)/(x+2)+(2-x)/[(x+2)(x-2)]
=(x+3)/(x+2)-1/(x+2)
=(x+3-1)/(x+2)
=(x+2)/(x+2)
=1请问下可以通分计算吗？虽然比较复杂，如果能，麻烦你写一下好吗？(x+3)/(x+2)+(2-x)/(x²-4)=(x+3)/(x+2)+(2-x)/[(x+2)(x-2)]=（x-2)(x+3)/[(x+2)(x-2)]+(2-x)/[(x+2)(x-2)]=(x²+x-6+2-x)/[(x+2)(x-2)]=（x²-4)/(x²-4)=1