设圆锥的底面半径为r,高为h,母线长l,则h=√(l²-r²)
依题意得S=πr²+πrl=πa²,得l=(a²-r²)/r,故
V=(1/3)πr²h
=(1/3)πr²√(l²-r²)
=(1/3)πr²√[(a²-r²)²/r²-r²]
=(aπ/3)r√(a²-2r²)
=(aπ/3√2)√2r√(a²-2r²)
≤(aπ√2/6)[2r²+(a²-2r²)]/2
=πa³√2/12(当且仅当2r²=a²-2r²,即r=a/2时,“=”取到)
zxqsyr 21:02:59