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(a²-a)² - 8(a-2)(a+1)-1 分解因式
人气:463 ℃ 时间:2020-09-11 22:40:08
解答
(a²-a)² - 8(a-2)(a+1)-1=(a²-a)²-8(a²-a-2)-1=(a²-a)²-8a²+8a+16-1
=(a²-a)²-8a(a²-1)+15=[(a²-a)-3][(a²-a)-5]
=(a²-a-3)(a²-a-5)=[(a-1/2)²-1/4-3][(a-1/2)²-1/4-5]
=[(a-1/2)²-13/4][(a-1/2)²-21/4]
=(a-1/2+√13/2)(a-1/2-√13/2)(a-1/2+√21/2)(a-1/2-√21/2)
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