UL |
RL |
U−UL | ||
|
6V |
RL |
U−6V |
10Ω |
当开关S闭合,滑片P滑到变阻器最大阻值位置时:
U′L |
RL |
U−U′L |
R |
4V |
RL |
U−4V |
20Ω |
由①②解得:
U=12V,RL=10Ω
P额=
| ||
RL |
(6V)2 |
10Ω |
(2)Q =I2Rt=(
U |
RL+R |
12V |
10Ω+20Ω |
答:(1)电源电压是12V,灯L的额定功率为3.6W;
(2)当变阻器连入电路的阻值为最大值时,电流通过它3min所产生的热量为576J
UL |
RL |
U−UL | ||
|
6V |
RL |
U−6V |
10Ω |
U′L |
RL |
U−U′L |
R |
4V |
RL |
U−4V |
20Ω |
| ||
RL |
(6V)2 |
10Ω |
U |
RL+R |
12V |
10Ω+20Ω |