> 数学 >
计算:a+2b+(4b^2/a-2b)-(4a^2b/a^2-4b^2)
人气:331 ℃ 时间:2019-11-09 03:57:02
解答
a+2b+(4b^2/a-2b)-(4a^2b/a^2-4b^2)
=[(a+2b)(a^2-4b^2)+4b^2(a+2b)-4a^2b]/(a^2-4b^2)
=(a^3-4ab^2+2a^2b-8b^3+4b^2a+8b^3-4a^2b)/(a^2-4b^2)
=(a^3-2a^2b)/(a^2-4b^2)
=a^2/(a+2b)
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版