Given that f(x)=2x^2-12x+11, for the domain x>=0, find the range of f?
人气：411 ℃ 时间：2020-05-08 01:29:16
解答
求f(x)的值域
f(x)=2x^2-12x+11
f(x)=2[(x-3)^2]-7
x≥0
根据图像得
f(x)有最小值-7
所以f（x)∈[-7,+∞）
the range of f
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