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(-1/125)^2/3-1/3log的底数1/2(1/27)*log的底数3(1/32)+4^(-1+log的底数4(2004))
人气:144 ℃ 时间:2020-09-09 05:26:59
解答
=1/25-log1/2(1/3)*log3(1/32)+4^-1*4^log4(2004)
=1/25-lg(3)/lg2*lg(2)^-5/lg3+1/4*2004
=1/25+5+501
=506又1/25是-1/125
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