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log2(2^x-1)log2(2^(x+2)-4=3
log2(2^x-1)log2(2^(x+2)-4)=3
人气:375 ℃ 时间:2020-05-12 05:05:48
解答
设t=log2(2^x-1)则log2(2^(x+2)-4)=2+t原式=t*(2+t)=3t=-3ort=1log2(2^x-1)=-32^x-1=1/82^x=9/8x=2log2(3)-3log2(2^x-1)=12^x-1=22^x=3x=log2(3)综上x=2log2(3)-3 or x=log2(3)
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