化简求值:2x²y-[x²y+2(xy²-xy)+y]+y,其中x²=2x+1,y=201_数学解答

化简求值:2x²y-[x²y+2(xy²-xy)+y]+y,其中x²=2x+1,y=2011/2012
2x²y-[x²y+2(x²y-xy)+y]+y,其中x²=2x+1,y=2011/2012

人气：259 ℃　时间：2020-04-05 22:43:26

解答

题目有问题,请核查
2x²y-[x²y+2(x²y-xy)+y]+y
=2x²y-x²y-2x²y+2xy-y+y
=-x²y+2xy
=-(x²-2x)y
=-y
=-2011/2012