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数学
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已知a=½m+1,b=½m+2,c=½m+4求a²+2ab+b²-2c(a+b)+c²的值
人气:139 ℃ 时间:2020-06-08 13:35:41
解答
原式=(a+b)²-2c(a+b)+c²
=(a+b-c)
=(½m+1+½m+2-½m-4)
=(½m-1)²
=¼m²-m+1
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