已知y<根号x-1+根号1-x+二分之一,化简y-x分之根号x²-2xy+y²
人气:353 ℃ 时间:2019-10-23 04:13:20
解答
根号则x-1>=0,x>=1
1-x>=0,x0
所以原式=√(x-y)²/(y-x)
=|x-y|/(y-x)
=(x-y)/(y-x)
=-1
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