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5.已知x = 0.67,y=0.33,求x^2 +y^2 +2xy-x-y的值
人气:372 ℃ 时间:2020-06-06 22:18:25
解答
x^2 +y^2 +2xy-x-y
=(x+y)^2-(x+y)
= (x+y)(x+y-1)
=0
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