已知 a2+b2+4a-2b+5=0,求2分之a2+b2-ab 急!
人气:176 ℃ 时间:2020-04-16 14:01:54
解答
即)a²+4a+4)+(b²-2b+1)=0
(a+2)²+(b-1)²=0
所以a+2=0,b-1=0
a=-2,b=1
所以原式=4+1+2=7
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