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当x=0.5 y=2时求(3xy-2x^2+0.5y^2)(3xy+2x^2-0.5y^2)的值
人气:170 ℃ 时间:2019-11-09 16:20:27
解答
(3xy-2x^2+0.5y^2)(3xy+2x^2-0.5y^2)
= [3xy-(2x^2-0.5y^2)][3xy+(2x^2-0.5y^2)]
= (3xy)^2 - (2x^2-0.5y^2)^2
= 9 - (0.5 - 2)^2
= 9 - 2.25
= 6.75
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