已知x^2+9y^2+4x-6y+5=0,求xy的值已知m^2+n^2-6m+10n+34=0则m+n=?_数学解答

已知x^2+9y^2+4x-6y+5=0,求xy的值已知m^2+n^2-6m+10n+34=0则m+n=?

人气：324 ℃　时间：2020-03-23 03:17:34

解答

因为x^2+9y^2+4x-6y+5=0,所以x^2+4x+4+9y^2-6y+1=0,所以（x-2）^2+（3y-1）^2=0,所以x=2,y=1/3.

因为m^2+n^2-6m+10n+34=0,所以（m-3）^2+（n-5）^2=0,所以m=3,n=5;所以m+n=8.