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证明sina*sinb=[cos(a-b)-cos(a+b)]/2
人气:198 ℃ 时间:2019-12-25 10:54:38
解答
cos(a-b)=cosacosb+sinasinb(1)
cos(a+b)=cosacosb-sinasinb(2)
(1)-(2)
cos(a-b)-cos(a+b)=2sinasinb
sinasinb=[cos(a-b)-cos(a+b)]/2
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