此题应该不止一问以AC为边向左作等边△ACF.再已EF为边作等边向下作等边△EFG,连接BG, FD, BF∴AC=AF=CF∠CAF=∠AFC=∠ACF=60° EF=FG=EG∠EFG=∠EGF=∠FEG=60°∵AB=AC∴∠ABC=∠ACB AF=...